How Many Moles of Nh3 Can Be Produced From 13.5 Mol of H2 and Excess N2

nh3-periodic-table

3 H2 (thou) + N2 (g)→ ii NH3(chiliad)a

In this commodity you lot can find the answer for How Many Moles of NH3 Can Be Produced from 13.5 mol of H2 and Excess N2. Also you tin detect answers for:

  • How many grams of NH3 can be produced from four.90 mol of N2 and excess H2
  • How many grams of H2 are needed to produce 12.74 grand of NH3?
  • How many molecules (not moles) of NH3 are produced from 1.05×10^-4 yard of H2?
nh3 periodic table, moles of nh3

How Many Moles of NH3 Can Be Produced from 13.5 mol of H2 and Excess N2?

For every 3 moles of H2, 2 of NH3 can be produced. If we multiply the amount of hydrogen by 2/3 and we can get the answer.

nine moles of NH3 are produced from xiii.5 mol of H2 and excess N2.

How many grams of NH3can exist produced from 4.90 mol ofN2 and excess H2?

Nii + 3H2 = 2NHiii

i mol of nitrogen + hydrogen produces 2(fourteen+3) = 34 grams NH3

4.9 mol of N and H produces 34 * 4.9 grams NH3

Respond is 166.6 grams of NH3 tin can exist produced from four.90 mol of N2 and excess H2.

How many grams of H2 are needed to produce 12.74 g of NH3?

1000 (NH3) = xiv.01 + 1.008*iii = 17.034

thou (NH3 = 12.74

north(NH3 = 12.74/17.034 = 0.749

For every two moles of NH3, you need 3 moles of H2.

0.749 * 3/2 moles of H2 = 1.12 mol

M(H2 = 2.016
grand = n*Grand = 1.12 mol * 2.016 one thousand/mol = 2.25

Most 2.25 grams of H2

Answer is 2.25 grams of H2 are needed to produce 12.74 g of NH3.

How many molecules (not moles) of NH3 are produced from one.05×x^-4 grand of H2?

grand(NH₃) = ane.05 × 10⁻⁴ g NH₃

M(NH₃) = 14.007 1000/mol Northward + (3 × i.008 g/mol H) = 17.031 one thousand NH₃/mol NH₃

northward(NH₃) = 1.05 × ten⁻⁴ yard NH₃/17.031 g NH₃/mol NH₃ = six.16 × 10^-six mol NH₃

Calculate the number of molecules of NH₃ in 6.16 × ten^-6 mol.

1 mole of molecules = 6.022 × x²³ molecules

6.sixteen × x^-6 mol NH₃ × 6.022 × 10²³ NH₃ molecules/mol NH₃ = 37.09 × 10^17 NH₃

The number of molecules of NH3 are produced from 1.05 × 10^-4 g is 37.09 × ten^17.

We tried to answer the question "How Many Moles of NH3 Can Be Produced from 13.v mol of H2 and Excess N2" in this commodity. And also we tried to find answers for "How many grams of NH3can exist produced from 4.ninety mol ofN2 and backlog H2?", "How many grams of H2 are needed to produce 12.74 one thousand of NH3" and "How many molecules (non moles) of NH3 are produced from i.05×10^-4 g of H2" If you lot need any help with other chemical science related problems, contact the states.

Don't forget to check out "How to Draw H2O Lewis Structure", "How to Depict CO Lewis Structure" and "How Many Valence Electrons Does Aluminum Have" articles to learn more than virtually chemistry.

Here is another bang-up source "CH3CH2CH3 Lewis Structure".

Also cheque out "What is the total number of valence electrons in CO2".

And check out "What is the Basis State Electron Configuration for O2–".

riosoicieffive1941.blogspot.com

Source: https://chemhelps.com/2022/02/02/how-many-moles-of-nh3-can-be-produced-from-13-5-mol-of-h2-and-excess-n2/

0 Response to "How Many Moles of Nh3 Can Be Produced From 13.5 Mol of H2 and Excess N2"

Post a Comment

Iklan Atas Artikel

Iklan Tengah Artikel 1

Iklan Tengah Artikel 2

Iklan Bawah Artikel